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🥑 Second and better one solution in Clear category for Words Order by vincent.tscherter
var wordsOrder = (a, b) => {
a = a.split(' ').filter( x=> b.includes(x))
a = [...new Set(a)] // rem duplicates
return b.reduce( (e, f, i) => e && f==a[i], true )
}
Jan. 6, 2021
