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primera solution in Clear category for [old] What Is Wrong With This Family? by RoyRacer
"use strict";
function isFamily(tree) {
let errors = 0;
for (let r in tree) {
let father = tree[r][0];
let son = tree[r][1];
let times = 0;
let brothers = [];
// TEST 1: SON CAN ONLY HAVE ONE FATHER
for (let r1 in tree) {
if (son === tree[r1][1] && father != tree[r1][0]) {errors++;}
}
// TEST 2: SON CANNOT BE A FATHER TO THEIR OWN FATHER
for (let r2 in tree) {
if (son === tree[r2][0] && father === tree[r2][1]) {errors++;}
if (father === tree[r2][0] && son != tree[r2][1]) {brothers.push(tree[r2][1])}
}
// TEST 3: SON CANNOT BE THE FATHER OF THEIR BROTHER
for (let bro in brothers) {
for (let r3 in tree){
if (brothers[bro] === tree[r3][1] && son === tree[r3][0]) {errors++;}
}
}
// TEST 4: NOT A STRANGER
for (let r4 in tree) {
if (tree.length > 1) {
if (father === tree[r4][0] || father === tree[r4][1]) {times++}
else if (son === tree[r4][0] || son === tree[r4][1]) {times++}
}
}
if (tree.length > 1 && times <= 1) {errors++}
}
return errors > 0 ? false : true;
}
var assert = require('assert');
if (!global.is_checking) {
assert.equal(isFamily([
['Logan', 'Mike']
]), true, 'One father, one son');
assert.equal(isFamily([
['Logan', 'Mike'],
['Logan', 'Jack']
]), true, 'Two sons');
assert.equal(isFamily([
['Logan', 'Mike'],
['Logan', 'Jack'],
['Mike', 'Alexander']
]), true, 'Grandfather');
assert.equal(isFamily([
['Logan', 'Mike'],
['Logan', 'Jack'],
['Mike', 'Logan']
]), false, 'Can you be a father for your father?');
assert.equal(isFamily([
['Logan', 'Mike'],
['Logan', 'Jack'],
['Mike', 'Jack']
]), false, 'Can you be a father for your brother?');
assert.equal(isFamily([
['Logan', 'William'],
['Logan', 'Jack'],
['Mike', 'Alexander']
]), false, 'Looks like Mike is stranger in Logan\'s family');
console.log("Looks like you know everything. It is time for 'Check'!");
}
Nov. 29, 2016
