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re🏭ed solution in Clear category for [old] Worth of Words by vincent.tscherter
var VALUES = {'e': 1, 'a': 1, 'i': 1, 'o': 1, 'n': 1, 'r': 1,
't': 1, 'l': 1, 's': 1, 'u': 1, 'd': 2, 'g': 2,
'b': 3, 'c': 3, 'm': 3, 'p': 3, 'f': 4, 'h': 4,
'v': 4, 'w': 4, 'y': 4, 'k': 5, 'j': 8, 'x': 8,
'q': 10, 'z': 10};
String.prototype.value = function() {
return [...this].reduce((a,c) => a + VALUES[c], 0)
}
var worthOfWords = words => words.sort( (a,b) => b.value() - a.value() )[0];
Dec. 14, 2018
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