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Short and clear one line solution solution in Creative category for [old] Fizz Buzz by Rool_Kach
const fizzBuzz = (n, a = n % 3 ? 0 : 'Fizz', b = n % 5 ? 0 : 'Buzz') => a && b ? "Fizz Buzz" : a || b || String(n);
Jan. 11, 2019
