First clear solution for [old] Digits Multiplication by nlupton - javascript coding challenges

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First solution in Clear category for [old] Digits Multiplication by nlupton

"use strict";

const digitsMultip = n =>
    n.toString()
     .split('')
     .map(Number)
     .reduce( (t,c) => c === 0 ? t : t * c)

var assert = require('assert');

if (!global.is_checking) {
    assert.equal(digitsMultip(123405), 120, "1st");
    assert.equal(digitsMultip(999), 729, "2nd");
    assert.equal(digitsMultip(1000), 1, "3rd");
    assert.equal(digitsMultip(1111), 1, "4th");
    console.log("Coding complete? Click 'Check' to review your tests and earn cool rewards!");
}

Dec. 3, 2018

Comments:

fabian_ on Sept. 10, 2019, 7:21 p.m.
<p>is .map(Number) necessary? Maybe coercion would work without it. </p>

nlupton on Sept. 18, 2019, 7:56 p.m.
<p>yeah, you could just rely on coercion (as long as `c === 0` was changed to `c == 0` but I've always preferred explicit coercion where I can, and using map(Number) will have a negligible performance impact.</p>

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