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First solution in Clear category for [old] Count Inversion by capback250
"use strict";
function countInversion(sequence){
let invers = 0;
for (let i = 0; i < sequence.length - 1; i++){
for (let j = i + 1; j < sequence.length; j++){
if (sequence[i] > sequence[j]) invers++;
}
}
return invers;
}
April 15, 2017
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