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First solution in Clear category for [old] Count Inversion by Moff
function countInversion(sequence) {
let result = 0;
for (let i = 0; i < sequence.length; i++) {
for (let j = i + 1; j < sequence.length; j++) {
if (sequence[j] < sequence[i])
result += 1;
}
}
return result;
}
July 6, 2017