Lightbulb Operating
Since you are here, it means that you’ve already solved 4 missions of the series. Your function can already adopt more than one light bulb in the date array to determine if the room is lit or not. And with the second and third elements the period we want to observe can be defined.
In the 5th mission, a fourth argument is added - the operating time of the light bulbs. By analogy with the previous missions - if it’s not passed, then the bulb works indefinitely.
The operating time argument is passed as a timedelta object. It shows how long the light bulb can work when it’s on. It has no cooling, which means that if our bulb can work for only one hour, then it can work for 30 minutes now and 30 minutes next year. After that it will turn itself off and will no longer respond to the button.
We still need to calculate how long the room has been lit.
Input: Four arguments and only the first one is required. The first one (els) is an array of Date objects (instead of Date object there can be an array of two Date and number), the second (start_watching) and the third ones (end_watching) is the Date objects or undefined. The fourth argument (operating) - integer - how long the lamp can work.
Output: A number of seconds as an integer.
Example:
sumLight([
new Date(2015, 1, 12, 10, 0, 0),
new Date(2015, 1, 12, 10, 0, 10),
[new Date(2015, 1, 12, 10, 0, 0), 2],
[new Date(2015, 1, 12, 10, 1, 0), 2],
]) == 60
sumLight([
[new Date(2015, 1, 12, 10, 0, 10), 3],
new Date(2015, 1, 12, 10, 0, 20),
[new Date(2015, 1, 12, 10, 0, 30), 3],
[new Date(2015, 1, 12, 10, 0, 30), 2],
new Date(2015, 1, 12, 10, 0, 40),
[new Date(2015, 1, 12, 10, 0, 50), 2],
[new Date(2015, 1, 12, 10, 1, 0), 3],
[new Date(2015, 1, 12, 10, 1, 20), 3],
]) == 60
sumLight([
new Date(2015, 1, 12, 10, 0, 0),
new Date(2015, 1, 12, 10, 0, 10),
[new Date(2015, 1, 12, 10, 0, 0), 2],
[new Date(2015, 1, 12, 10, 1, 0), 2],
], new Date(2015, 1, 12, 10, 0, 20), new Date(2015, 1, 12, 10, 1, 0)) == 40
sumLight([
[new Date(2015, 1, 12, 10, 0, 10), 3],
new Date(2015, 1, 12, 10, 0, 20),
[new Date(2015, 1, 12, 10, 0, 30), 3],
[new Date(2015, 1, 12, 10, 0, 30), 2],
], new Date(2015, 1, 12, 10, 0, 10), new Date(2015, 1, 12, 10, 0, 30)) == 20
Precondition:
- The array of pressing the button is always sorted in ascending order.
- The array of pressing the button has no repeated elements.
- The minimum possible date is 1970-01-01
- The maximum possible date is 9999-12-31
CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=js config --key=
Sync solutions into your local folder
checkio sync
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin
checkio install-plugin --ff
checkio install-plugin --chromium
Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.
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