Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Count Divisibles in Range (simplified) by mortonfox
import assert from "assert";
function countDivisible(n: number, k: number): number {
return n/k|0;
}
console.log("Example:");
console.log(countDivisible(2, 1));
// These "asserts" are used for self-checking
assert.strictEqual(countDivisible(10, 2), 5);
assert.strictEqual(countDivisible(10, 3), 3);
assert.strictEqual(countDivisible(10, 5), 2);
assert.strictEqual(countDivisible(15, 4), 3);
assert.strictEqual(countDivisible(20, 6), 3);
assert.strictEqual(countDivisible(100, 10), 10);
assert.strictEqual(countDivisible(200, 25), 8);
assert.strictEqual(countDivisible(50, 7), 7);
assert.strictEqual(countDivisible(60, 8), 7);
assert.strictEqual(countDivisible(70, 9), 7);
console.log("Coding complete? Click 'Check Solution' to earn rewards!");
Oct. 30, 2023
Comments: