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Bigger Price solution in Clear category for Bigger Price by Atadolfo
import assert from "assert";
interface obj {
name: string;
price: number;
}
var biggerPrice = (limit: number, data: obj[]): obj[] => data.sort((a: obj, b: obj) => b.price - a.price).filter((v: obj, i: number) => i < limit);
console.log('Example:')
console.log(biggerPrice(2, [
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1}
]))
assert.deepEqual(biggerPrice(2, [
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1}
]), [
{"name": "wine", "price": 138},
{"name": "bread", "price": 100}
])
assert.deepEqual(biggerPrice(1, [
{"name": "pen", "price": 5},
{"name": "whiteboard", "price": 170}
]), [{"name": "whiteboard", "price": 170}])
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April 25, 2020