Beat The Previous
Given a string of digits guaranteed to only contain ordinary integer digit characters 0 to 9, create and return the array of increasing integers acquired from reading these digits in order from left to right. The first integer in the result list is made up from the first digit of the string. After that, each element is an integer that consists of as many following consecutive digits as are needed to make that integer strictly larger than the previous integer. The leftover digits at the end of the digit string that do not form a sufficiently large integer are ignored.
This mission is quite easy, but we also have got a harder version - Staircase. Try it!
Input: String (string).
Output: Array of integers (number).
Examples:
assert.deepStrictEqual(beatPrevious("600005"), [6]);
assert.deepStrictEqual(beatPrevious("6000050"), [6, 50]);
assert.deepStrictEqual(beatPrevious("045349"), [0, 4, 5, 34]);
assert.deepStrictEqual(
beatPrevious("77777777777777777777777"),
[7, 77, 777, 7777, 77777, 777777]
);
The mission was taken from Python CCPS 109. It is taught for Ryerson Chang School of Continuing Education by Ilkka Kokkarinen
CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=js config --key=
Sync solutions into your local folder
checkio sync
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin
checkio install-plugin --ff
checkio install-plugin --chromium
Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.
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