😲 no Upper l<{} creative solution for All Upper I by vincent.tscherter - javascript coding challenges

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😲 no Upper l<{} solution in Creative category for All Upper I by vincent.tscherter

var isAllUpper = t => [...t].every(l=>l<{})

Dec. 3, 2020

Comments:

PHANTOM0308 on April 29, 2022, 8:54 p.m.
Great Answer, but I am wondering why ASCII code of an Object as String is 91? Isn't 91 is for character '['?

vincent.tscherter on April 30, 2022, 8:57 a.m.
<pre class='brush: javascript'>'Z'<{} // true 'a'<{} // false 'Z'<[] // false </pre> now why <pre class='brush: javascript'>String([]) gives you '' String({}) gives you '[object Object]' </pre> and <pre class='brush: javascript'>[</pre> is exactly what you need. A char that is between <pre class='brush: javascript'>'Z'</pre> and <pre class='brush: javascript'>'a'</pre>. Check on <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Less_than">https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Less_than</a>

vincent.tscherter on April 30, 2022, 9:47 a.m.
So I use <pre class='brush: javascript'>{}</pre> inststead of <pre class='brush: javascript'>"["</pre> which is one characted less to write. 🏌️‍♀️

PHANTOM0308 on April 30, 2022, 10:37 p.m.
Oh yeah, the String conversion of Object gives [object Object], so the first character is used for comparison, which is '['. Man, thanks for your reply.

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